C++核心準(zhǔn)則C.167:為具有約定俗成?語義的操作使用運(yùn)算符

C.167: Use an operator for an operation with its conventional meaning

C.167:為具有約定俗成語義的操作使用運(yùn)算符

Reason(原因)

Readability. Convention. Reusability. Support for generic code。

可讀性。遵守慣例?？蓮?fù)用性。支持泛化代碼。

Example(示例)

void cout_my_class(const My_class& c) // confusing, not conventional,not generic
{
    std::cout << /* class members here */;
}

std::ostream& operator<<(std::ostream& os, const my_class& c) // OK
{
    return os << /* class members here */;
}

By itself,?cout_my_class?would be OK, but it is not usable/composable with code that rely on the?<

如果只考慮自己的話，cout_my_class還不錯(cuò)，但是它無法在通過<<運(yùn)算符輸出的代碼中使用(或者和這樣的代碼一起使用)。

My_class var { /* ... */ };
// ...
cout << "var = " << var << '\n';

Note(注意)

There are strong and vigorous conventions for the meaning most operators, such as

很多操作符具有強(qiáng)烈而且活躍的約定含義，例如：

• comparisons (==,?!=,?<,?<=,?>, and?>=),

• 比較運(yùn)算符

• arithmetic operations (+,?-,?*,?/, and?%)

• 數(shù)學(xué)運(yùn)算符

• access operations (.,?->, unary?*, and?[])

• 訪問運(yùn)算符

• assignment (=)

• 賦值運(yùn)算符

Don't define those unconventionally and don't invent your own names for them.

不要違反慣例定義這些運(yùn)算符，也不要為它們發(fā)明新名稱。

Enforcement(實(shí)施建議)

Tricky. Requires semantic insight.

不容易。需要語義方面的深入理解。

原文鏈接：

https://github.com/isocpp/CppCoreGuidelines/blob/master/CppCoreGuidelines.md#c167-use-an-operator-for-an-operation-with-its-conventional-meaning

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