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          詳解synchronized鎖的各種用法及注意事項

          共 13278字,需瀏覽 27分鐘

           ·

          2021-02-19 14:13

          1 前言

          本文主要通過簡單的demo來闡述synchronized鎖的各種用法以及使用synchronized鎖的相關注意事項,記錄下來同時也方便自己記憶。

          synchronized鎖是jvm內(nèi)置的鎖,不同于ReentrantLock鎖。synchronized關鍵字可以修飾方法,也可以修飾代碼塊。synchronized關鍵字修飾方法時可以修飾靜態(tài)方法,也可以修飾非靜態(tài)方法;同樣,synchronized關鍵字修飾代碼塊時可以修飾對象,也可以修飾類。當然,synchronized修飾靜態(tài)方法/類和非靜態(tài)方法/對象時的作用范圍是不同的。下面通過各種demo來詳解synchronized的各種用法及注意事項。

          2 synchronized類鎖

          這里所說的synchronized類鎖的作用范圍是類級別的,不會因為同一個類的不同對象執(zhí)行而失效。

          2.1 synchronized修飾同一個類的兩個靜態(tài)方法時互斥

          public?class?SynchronizeAndClassLock?{
          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????new?Thread(()?->?{
          ????????????//?new了一個ClassLock對象
          ????????????new?ClassLock().test1();
          ????????}).start();

          ????????new?Thread(()?->?{
          ????????????//?new了另一個ClassLock對象
          ????????????new?ClassLock().test2();
          ????????}).start();
          ????}

          }
          class?ClassLock?{
          ????public?synchronized?static?void?test1(){
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????try?{
          ????????????TimeUnit.SECONDS.sleep(1);
          ????????}?catch?(Exception?e)?{}
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????}
          ?//?【注意】public static void test2(){?不會互斥,因為此時test2沒有使用類鎖。
          ????public?synchronized?static?void?test2(){
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????try?{
          ????????????TimeUnit.SECONDS.sleep(1);
          ????????}?catch?(Exception?e)?{}
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????}
          }

          運行結果:

          【結論】兩個線程分別同時執(zhí)行同一個類產(chǎn)生的不同對象的兩個不同?synchronized static方法,類鎖生效,雖然是不同對象,因為兩個線程使用的是同一個類鎖。反過來,假如test2方法沒有synchronized修飾的話,只有test1方法有被synchronized修飾,此時兩個方法也不會互斥,一個有鎖,一個沒有鎖,自然不會互斥。

          2.2 synchronized分別修飾同一個類的靜態(tài)方法和當前類時互斥

          public?class?SynchronizeAndClassLock2?{
          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????new?Thread(()?->?{
          ????????????// new了一個ClassLock2對象
          ????????????new?ClassLock2().test1();
          ????????????//?ClassLock2.test1();
          ????????}).start();

          ????????new?Thread(()?->?{
          ????????????//?new了另一個ClassLock2對象
          ????????????new?ClassLock2().test2();
          ????????????//?ClassLock2.test2();
          ????????}).start();
          ????}

          }
          class?ClassLock2?{
          ????public?synchronized?static?void?test1(){
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????try?{
          ????????????TimeUnit.SECONDS.sleep(1);
          ????????}?catch?(Exception?e)?{}
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????}

          ????public?static?void?test2(){
          ?????//?【注意】synchronized?(SynchronizeAndClassLock2.class)不會互斥
          ????????synchronized?(ClassLock2.class)?{
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????????try?{
          ????????????????TimeUnit.SECONDS.sleep(1);
          ????????????}?catch?(Exception?e)?{}
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????????}
          ????}
          }

          運行結果:

          【結論】兩個線程同時分別執(zhí)行一個被synchronized修飾static方法,一個有synchnized(該類)代碼塊的static方法,鎖生效,雖然是不同對象,因為兩個線程使用的同一個類鎖。反過來,如果是修飾的不同類,因為類鎖不同,肯定不會互斥,比如將test2方法的synchronized (ClassLock2.class)這句代碼改成synchronized (SynchronizeAndClassLock2.class),此時不會互斥。

          2.3 synchronized分別修飾同一個靜態(tài)對象時互斥

          public?class?SynchronizeAndClassLock10?{

          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????new?Thread(()?->?{
          ????????????new?RunObject1().test1();
          ????????}).start();

          ????????new?Thread(()?->?{
          ????????????new?RunObject2().test2();
          ????????}).start();
          ????}
          }

          class?RunObject1?{
          ????public?static?void?test1(){
          ?????//?【1】synchronized?(StaticLock2.staticLock1)?{
          ????????synchronized?(StaticLock2.staticLock)?{
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????????try?{
          ????????????????TimeUnit.SECONDS.sleep(1);
          ????????????}?catch?(Exception?e)?{}
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????????}
          ????}
          }


          class?RunObject2?{
          ????public?static?void?test2()?{
          ?????//?【2】synchronized?(StaticLock2.staticLock2)?{
          ????????synchronized?(StaticLock2.staticLock)?{
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????????try?{
          ????????????????TimeUnit.SECONDS.sleep(1);
          ????????????}?catch?(Exception?e)?{}
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????????}
          ????}
          }

          class?StaticLock2?{
          ????public?static?Object?staticLock?=?new?Object();
          }

          運行結果:

          【結論】synchronized分別修飾同一個類的靜態(tài)對象時互斥,反過來,如果是修飾不同的靜態(tài)對象,肯定不會互斥,比如將上面代碼中標【1】【2】synchronized代碼結合使用。

          3 synchronized對象鎖

          這里說的synchronized對象鎖的作用范圍是對象級別的即僅僅作用于同一個對象,如果是同一個類的兩個不同的對象是不會互斥的,即沒有效果的。

          3.1 synchronized修飾同一個類對象的兩個非靜態(tài)方法時互斥

          public?class?SynchronizeAndObjectLock2?{
          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????//?【注意】當且僅當是同一個SynchronizeAndObjectLock2對象
          ????????SynchronizeAndObjectLock2?synchronizeAndObjectLock2?=?new?SynchronizeAndObjectLock2();
          ????????new?Thread(()?->?{
          ????????????synchronizeAndObjectLock2.test1();
          ????????}).start();

          ????????new?Thread(()?->?{
          ????????????synchronizeAndObjectLock2.test2();
          ????????}).start();
          ????}
          ????public?synchronized?void?test1(){
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????try?{
          ????????????TimeUnit.SECONDS.sleep(1);
          ????????}?catch?(Exception?e)?{}
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????}

          ????public?synchronized?void?test2(){
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????try?{
          ????????????TimeUnit.SECONDS.sleep(1);
          ????????}?catch?(Exception?e)?{}
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????}
          }

          運行結果:

          【結論】兩個線程同時執(zhí)行被synchronized修飾的相同對象的不同(相同)方法,鎖生效,因為兩個線程使用的是相同的對象鎖

          3.2 synchronized分別修飾同一個類對象的非靜態(tài)方法和當前對象時互斥

          public?class?SynchronizeAndObjectLock3?{
          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????//?【注意】當且僅當是同一個SynchronizeAndObjectLock3對象
          ????????SynchronizeAndObjectLock3?synchronizeAndObjectLock3?=?new?SynchronizeAndObjectLock3();
          ????????new?Thread(()?->?{
          ????????????synchronizeAndObjectLock3.test1();
          ????????}).start();

          ????????new?Thread(()?->?{
          ????????????synchronizeAndObjectLock3.test2();
          ????????}).start();
          ????}
          ????public?void?test1(){
          ????????synchronized(this)?{
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????????try?{
          ????????????????TimeUnit.SECONDS.sleep(1);
          ????????????}?catch?(Exception?e)?{}
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????????}

          ????}

          ????public?synchronized?void?test2(){
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????try?{
          ????????????TimeUnit.SECONDS.sleep(1);
          ????????}?catch?(Exception?e)?{}
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????}
          }

          運行結果:

          【結論】snchronized修飾非靜態(tài)方法與synchronized(this)互斥,可見,snchronized修飾非靜態(tài)方法實質(zhì)鎖的是當前對象。

          3.3 synchronized修飾不同對象的兩個非靜態(tài)方法時不會互斥

          public?class?SynchronizeAndObjectLock?{
          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????new?Thread(()?->?{
          ????????????//?這里new?了一個SynchronizeAndObjectLock對象
          ????????????new?SynchronizeAndObjectLock().test1();
          ????????}).start();

          ????????new?Thread(()?->?{
          ????????????//?這里new?了另一個SynchronizeAndObjectLock對象
          ????????????new?SynchronizeAndObjectLock().test2();
          ????????}).start();
          ????}
          ????public?synchronized?void?test1(){
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????try?{
          ????????????TimeUnit.SECONDS.sleep(1);
          ????????}?catch?(Exception?e)?{}
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????}

          ????public?synchronized?void?test2(){
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????try?{
          ????????????TimeUnit.SECONDS.sleep(1);
          ????????}?catch?(Exception?e)?{}
          ????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????}
          }

          運行結果:

          【結論】兩個線程同時執(zhí)行被synchronized修飾的不同對象的不同(相同)方法,鎖未生效,因為兩個線程使用的是不同的對象鎖。

          3.4 synchronized代碼塊修飾同一個對象時互斥

          public?class?SynchronizeAndObjectLock5?{
          ????private?Object?objectLock?=?new?Object();

          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????
          ????????SynchronizeAndObjectLock5?synchronizeAndObjectLock5?=?new?SynchronizeAndObjectLock5();
          ????????new?Thread(()?->?{
          ????????????synchronizeAndObjectLock5.test1();
          ????????}).start();

          ????????new?Thread(()?->?{
          ????????????synchronizeAndObjectLock5.test2();
          ????????}).start();
          ????}
          ????public?void?test1(){
          ????????synchronized(objectLock)?{
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????????try?{
          ????????????????TimeUnit.SECONDS.sleep(1);
          ????????????}?catch?(Exception?e)?{}
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????????}

          ????}

          ????public?void?test2(){
          ????????synchronized(objectLock)?{
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????????try?{
          ????????????????TimeUnit.SECONDS.sleep(1);
          ????????????}?catch?(Exception?e)?{}
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????????}
          ????}
          }

          運行結果:

          【結論】synchronized代碼塊修飾同一個對象時互斥,若synchronized代碼塊修飾的是不同對象,那么不會互斥。

          4 synchronized修飾當前類和當前對象時不會互斥

          public?class?ClassAndObjectLock?{
          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????new?Thread(()?->?{
          ????????????ClassAndObjectLock.test1();
          ????????}).start();

          ????????new?Thread(()?->?{
          ????????????new?ClassAndObjectLock().test2();
          ????????}).start();
          ????}
          ????public?static?void?test1(){
          ????????synchronized?(ClassAndObjectLock.class)?{
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????????try?{
          ????????????????TimeUnit.SECONDS.sleep(1);
          ????????????}?catch?(Exception?e)?{}
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????????}
          ????}

          ????public?void?test2(){
          ????????synchronized?(this)?{
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?begin...");
          ????????????try?{
          ????????????????TimeUnit.SECONDS.sleep(1);
          ????????????}?catch?(Exception?e)?{}
          ????????????System.out.println(new?Date()?+?"?"?+?Thread.currentThread().getName()?+?"?end...");
          ????????}
          ????}
          }

          運行結果:

          【結論】可見,類鎖和對象鎖是相互獨立的,互不相斥。

          5 synchronized鎖注意事項

          5.1 synchronized鎖不能被中斷

          為了模擬synchronized鎖不可中斷,下面先讓兩個線程進入死鎖,然后再用main線程去中斷其中一個線程,看被中斷的線程能否釋放鎖并被喚醒。

          public?class?DeadLockCannotInterruptDemo?{
          ????private?static?Object?lock1?=?new?Object();
          ????private?static?Object?lock2?=?new?Object();

          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????Thread?threadA?=?new?Thread(new?Runnable()?{
          ????????????@Override
          ????????????public?void?run()?{
          ????????????????synchronized?(lock1)?{
          ????????????????????System.out.println(Thread.currentThread().getName()?+?"?get?lock1");
          ????????????????????try?{
          ????????????????????????Thread.sleep(10);
          ????????????????????????synchronized?(lock2)?{
          ????????????????????????????System.out.println(Thread.currentThread().getName()?+?"?get?lock2");
          ????????????????????????}
          ????????????????????}?catch?(InterruptedException?e)?{
          ????????????????????????e.printStackTrace();
          ????????????????????}
          ????????????????}
          ????????????}
          ????????});

          ????????Thread?threadB?=?new?Thread(new?Runnable()?{
          ????????????@Override
          ????????????public?void?run()?{
          ????????????????synchronized?(lock2)?{
          ????????????????????System.out.println(Thread.currentThread().getName()?+?"?get?lock2");
          ????????????????????try?{
          ????????????????????????Thread.sleep(10);
          ????????????????????????synchronized?(lock1)?{
          ????????????????????????????System.out.println(Thread.currentThread().getName()?+?"?get?lock1");
          ????????????????????????}
          ????????????????????}?catch?(InterruptedException?e)?{
          ????????????????????????e.printStackTrace();
          ????????????????????}
          ????????????????}
          ????????????}
          ????????});

          ????????threadA.start();
          ????????threadB.start();

          ????????TimeUnit.SECONDS.sleep(3);
          ????????System.out.println("main?thread?begin?to?interrupt?"?+?threadA.getName()?+?"?and?"?+?threadA.getName()?+?"?will?release?lock1...");
          ????????threadA.interrupt();
          ????}
          }

          運行結果:

          【結論】如上圖,main線程中斷Thread-0后,Thread-0并不會釋放鎖并醒過來。同樣的,ReentrantLocktryLocklockInterruptibly是可以被中斷的。

          5.2 synchronized鎖可重入

          5.2.1 不同方法,synchronized是可重入的

          public?class?SynchronizeAndReentrant?{
          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????SynchronizeAndReentrant?synchronizeAndReentrant?=?new?SynchronizeAndReentrant();
          ????????synchronizeAndReentrant.test1();
          ????}
          ????public?synchronized?void?test1(){
          ????????System.out.println("?test1?method?is?called...");
          ????????test2();
          ????}

          ????public?synchronized?void?test2(){
          ????????System.out.println("?test2?method?is?called...");
          ????}
          }

          運行結果:

          5.2.2 相同方法,synchronized是可重入的

          public?class?SynchronizeAndReentrant2?{
          ????int?i?=?1;
          ????public?static?void?main(String[]?args)?throws?Exception?{
          ????????SynchronizeAndReentrant2?synchronizeAndReentrant?=?new?SynchronizeAndReentrant2();
          ????????synchronizeAndReentrant.test1();
          ????}
          ????public?synchronized?void?test1(){

          ????????System.out.println("?test1?method?is?called?"?+?i++?+?"st?time..."?);
          ????????while(i?5)?{
          ????????????test1();
          ????????}
          ????}
          }

          運行結果:

          5.3 synchronized鎖不帶超時功能

          synchronized鎖不帶超時功能,而ReentrantLocktryLock是具備帶超時功能的,在指定時間沒獲取到鎖,該線程會蘇醒,有助于預防死鎖的產(chǎn)生。

          5.4 喚醒/等待需要synchronized鎖

          public?class?NotifyNeedSynchronized?{
          ????public?static?Object?lock?=?new?Object();
          ????public?static?void?main(String[]?args)?throws?Exception{
          ????????//?拋出IllegalMonitorStateException
          ????????//lock.notify();
          ????????lock.wait();
          ????}
          }

          運行結果:

          【結論】使用Objectnotifywait等方法時,必須要使用synchronized鎖,否則會拋出IllegalMonitorStateException

          5.5 使用synchronized鎖時盡量縮小范圍以保證性能

          使用synchronized鎖時,為了盡可能提高性能,我們應該盡量縮小鎖的范圍。能不鎖方法就不鎖方法,推薦盡量使用synchronized代碼塊來降低鎖的范圍。以下面的一段netty源碼為例:

          //?ServerBootstrap.java

          public??ServerBootstrap?childOption(ChannelOption?childOption,?T?value)?{
          ????if?(childOption?==?null)?{
          ????????throw?new?NullPointerException("childOption");
          ????}
          ????if?(value?==?null)?{
          ????????synchronized?(childOptions)?{
          ????????????childOptions.remove(childOption);
          ????????}
          ????}?else?{
          ????????synchronized?(childOptions)?{
          ????????????childOptions.put(childOption,?value);
          ????????}
          ????}
          ????return?this;
          }

          可見,找到并發(fā)訪問代碼的臨界區(qū),并不用synchronized鎖全部代碼,盡量避免使用synchronized來修飾方法。

          6 總結

          本文對synchronized的各種用法及注意事項通過demo簡單梳理了下,后面有時間會探討下synchronized的原理。

          歡迎關注【源碼筆記】公眾號,Github地址: https://github.com/yuanmabiji/Java-SourceCode-Blogs


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