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          Spring Boot 實(shí)現(xiàn)限制賬戶(hù)登錄數(shù)

          共 4641字,需瀏覽 10分鐘

           ·

          2020-09-30 06:53

          關(guān)注泥瓦匠”,回復(fù)“1024”,領(lǐng)取精選技術(shù)資料


          作者:殷天文?www.jianshu.com/p/b6f5ec98d790

          通常系統(tǒng)都會(huì)限制同一個(gè)賬號(hào)的登錄人數(shù),多人登錄要么限制后者登錄,要么踢出前者,Spring Security 提供了這樣的功能,本文講解一下在沒(méi)有使用Security的時(shí)候如何手動(dòng)實(shí)現(xiàn)這個(gè)功能

          如果你是使用 Shiro + Session 的模式,可以閱讀此文

          demo 技術(shù)選型


          • SpringBoot

          • JWT

          • Filter

          • Redis + Redisson


          JWT(token)存儲(chǔ)在Redis中,類(lèi)似 JSessionId-Session的關(guān)系,用戶(hù)登錄后每次請(qǐng)求在Header中攜帶jwt
          如果你是使用session的話(huà),也完全可以借鑒本文的思路,只是代碼上需要加些改動(dòng)

          兩種實(shí)現(xiàn)思路


          比較時(shí)間戳

          維護(hù)一個(gè) username: jwtToken 這樣的一個(gè) key-value 在Reids中, Filter邏輯如下

          圖片不清可點(diǎn)開(kāi)放大


          public?class?CompareKickOutFilter?extends?KickOutFilter?{

          ????@Autowired
          ????private?UserService?userService;

          ????@Override
          ????public?boolean?isAccessAllowed(HttpServletRequest?request,?HttpServletResponse?response)?{
          ????????String?token?=?request.getHeader("Authorization");
          ????????String?username?=?JWTUtil.getUsername(token);
          ????????String?userKey?=?PREFIX?+?username;

          ????????RBucket?bucket?=?redissonClient.getBucket(userKey);
          ????????String?redisToken?=?bucket.get();

          ????????if?(token.equals(redisToken))?{
          ????????????return?true;

          ????????}?else?if?(StringUtils.isBlank(redisToken))?{
          ????????????bucket.set(token);

          ????????}?else?{
          ????????????Long?redisTokenUnixTime?=?JWTUtil.getClaim(redisToken,?"createTime").asLong();
          ????????????Long?tokenUnixTime?=?JWTUtil.getClaim(token,?"createTime").asLong();

          ????????????//?token?>?redisToken?則覆蓋
          ????????????if?(tokenUnixTime.compareTo(redisTokenUnixTime)?>?0)?{
          ????????????????bucket.set(token);

          ????????????}?else?{
          ????????????????//?注銷(xiāo)當(dāng)前token
          ????????????????userService.logout(token);
          ????????????????sendJsonResponse(response,?4001,?"您的賬號(hào)已在其他設(shè)備登錄");
          ????????????????return?false;

          ????????????}

          ????????}

          ????????return?true;

          ????}
          }

          隊(duì)列踢出

          public?class?QueueKickOutFilter?extends?KickOutFilter?{
          ????/**
          ?????*?踢出之前登錄的/之后登錄的用戶(hù)?默認(rèn)踢出之前登錄的用戶(hù)
          ?????*/

          ????private?boolean?kickoutAfter?=?false;
          ????/**
          ?????*?同一個(gè)帳號(hào)最大會(huì)話(huà)數(shù)?默認(rèn)1
          ?????*/

          ????private?int?maxSession?=?1;

          ????public?void?setKickoutAfter(boolean?kickoutAfter)?{
          ????????this.kickoutAfter?=?kickoutAfter;
          ????}

          ????public?void?setMaxSession(int?maxSession)?{
          ????????this.maxSession?=?maxSession;
          ????}

          ????@Override
          ????public?boolean?isAccessAllowed(HttpServletRequest?request,?HttpServletResponse?response)?throws?Exception?
          {
          ????????String?token?=?request.getHeader("Authorization");
          ????????UserBO?currentSession?=?CurrentUser.get();
          ????????Assert.notNull(currentSession,?"currentSession?cannot?null");
          ????????String?username?=?currentSession.getUsername();
          ????????String?userKey?=?PREFIX?+?"deque_"?+?username;
          ????????String?lockKey?=?PREFIX_LOCK?+?username;

          ????????RLock?lock?=?redissonClient.getLock(lockKey);

          ????????lock.lock(2,?TimeUnit.SECONDS);

          ????????try?{
          ????????????RDeque?deque?=?redissonClient.getDeque(userKey);

          ????????????//?如果隊(duì)列里沒(méi)有此token,且用戶(hù)沒(méi)有被踢出;放入隊(duì)列
          ????????????if?(!deque.contains(token)?&&?currentSession.isKickout()?==?false)?{
          ????????????????deque.push(token);
          ????????????}

          ????????????//?如果隊(duì)列里的sessionId數(shù)超出最大會(huì)話(huà)數(shù),開(kāi)始踢人
          ????????????while?(deque.size()?>?maxSession)?{
          ????????????????String?kickoutSessionId;
          ????????????????if?(kickoutAfter)?{?//?如果踢出后者
          ????????????????????kickoutSessionId?=?deque.removeFirst();
          ????????????????}?else?{?//?否則踢出前者
          ????????????????????kickoutSessionId?=?deque.removeLast();
          ????????????????}

          ????????????????try?{
          ????????????????????RBucket?bucket?=?redissonClient.getBucket(kickoutSessionId);
          ????????????????????UserBO?kickoutSession?=?bucket.get();

          ????????????????????if?(kickoutSession?!=?null)?{
          ????????????????????????//?設(shè)置會(huì)話(huà)的kickout屬性表示踢出了
          ????????????????????????kickoutSession.setKickout(true);
          ????????????????????????bucket.set(kickoutSession);
          ????????????????????}

          ????????????????}?catch?(Exception?e)?{
          ????????????????}

          ????????????}

          ????????????//?如果被踢出了,直接退出,重定向到踢出后的地址
          ????????????if?(currentSession.isKickout())?{
          ????????????????//?會(huì)話(huà)被踢出了
          ????????????????try?{
          ????????????????????//?注銷(xiāo)
          ????????????????????userService.logout(token);
          ????????????????????sendJsonResponse(response,?4001,?"您的賬號(hào)已在其他設(shè)備登錄");

          ????????????????}?catch?(Exception?e)?{
          ????????????????}

          ????????????????return?false;

          ????????????}

          ????????}?finally?{
          ????????????if?(lock.isHeldByCurrentThread())?{
          ????????????????lock.unlock();
          ????????????????LOGGER.info(Thread.currentThread().getName()?+?"?unlock");

          ????????????}?else?{
          ????????????????LOGGER.info(Thread.currentThread().getName()?+?"?already?automatically?release?lock");
          ????????????}
          ????????}

          ????????return?true;
          ????}

          }


          比較兩種方法


          第一種方法邏輯簡(jiǎn)單粗暴, 只維護(hù)一個(gè)key-value 不需要使用鎖,非要說(shuō)缺點(diǎn)的話(huà)沒(méi)有第二種方法靈活。

          第二種方法我很喜歡,代碼很優(yōu)雅靈活,但是邏輯相對(duì)麻煩一些,而且為了保證線(xiàn)程安全地操作隊(duì)列,要使用分布式鎖。目前我們項(xiàng)目中使用的是第一種方法

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