<kbd id="afajh"><form id="afajh"></form></kbd>
<strong id="afajh"><dl id="afajh"></dl></strong>
    <del id="afajh"><form id="afajh"></form></del>
        1. <th id="afajh"><progress id="afajh"></progress></th>
          <b id="afajh"><abbr id="afajh"></abbr></b>
          <th id="afajh"><progress id="afajh"></progress></th>

          你知道這20個數(shù)組方法是怎么實現(xiàn)的嗎?

          共 18736字,需瀏覽 38分鐘

           ·

          2022-07-09 16:03

          英文 | https://javascript.plainenglish.io/20-javascript-array-methods-every-developer-should-know-6c04cc7a557d

          翻譯 | 楊小愛


          前言
          你們一定對JavaScript中的數(shù)組很熟悉,我們每天都會用到它的各種方法,比如push、pop、forEach、map……等等。
          但是僅僅使用它就足夠了嗎?如此出色,您一定不想停在這里。我想和你一起挑戰(zhàn)實現(xiàn)20+數(shù)組方法的功能。
          1、forEach
          forEach 是我們工作中非常常用的數(shù)組方法,實現(xiàn)起來也比較簡單。這是我們需要完成的第一個功能。
          代碼
          Array.prototype.forEach2 = function (callback, thisCtx) {  if (typeof callback !== 'function') {    throw `${callback} is not a function`  }
          const length = this.length let i = 0
          while (i < length) { // Deleted, the newly added element index i is not in the array, so it will not be accessed if (this.hasOwnProperty(i)) { callback.call(thisCtx, this[ i ], i, this) }
          i++ }}
          測試一下
          let demoArr = [ 1, 2, 3, 4, , 5 ]
          demoArr.forEach2((it, i) => { if (i === 1) { // 5 will not be printed out demoArr.push(5) } else if (i === 2) { // 4 will not be printed out, but "4-4" will be printed out demoArr.splice(3, 1, '4-4') }
          console.log(it)})
          /* 1 2 3 4-4 5*/
          哇,恭喜!我們已經(jīng)實現(xiàn)了 forEach 的功能。
          2、map
          你一般用map做什么?大多數(shù)時候是將一個數(shù)組轉(zhuǎn)換為另一個數(shù)組。
          代碼
          Array.prototype.map2 = function (callback, thisCtx) {  if (typeof callback !== 'function') {    throw `${callback} is not a function`  }
          const length = this.length let i = 0 // The return value of the map method is a new array let newArray = []
          while (i < length) { // Deleted and uninitialized values will not be accessed if (this.hasOwnProperty(i)) { newArray.push(callback.call(thisCtx, this[ i ], i, this)) }
          i++ } // Return new array return newArray}
          測試一下
          let arr = [ 0, 1, 2, 3, 4,, 5 ]
          let arr2 = arr.map2(function (it, i, array) { console.log(it, i, array, this) return it * it}, { name: 'fatfish' })
          console.log(arr2) // [0, 1, 4, 9, 16, 25]
          朋友們,你們覺得不難嗎?那是因為你太厲害了。
          3、every
          every() 方法測試數(shù)組中的所有元素是否通過提供的函數(shù)實現(xiàn)的測試。它返回一個布爾值。
          每種方法都有你以前可能沒有注意到的三點,它們是什么?
          • 在空數(shù)組上調(diào)用 every 方法將返回 true。
          • 回調(diào)方法只會被已經(jīng)賦值的索引調(diào)用。
          • 如果值被刪除,回調(diào)將不會被調(diào)用
          let emptyArr = []// Calling every method on an empty array returns trueconsole.log(emptyArr.every((it) => it > 0)) // true// The `callback` method will only be called by an index that has already been assigned a value.let arr = [ 0, 1, 2, 3, 4,, 5, -1 ]// The `callback` method will not be called when an array value is deleted or an index that has never been assigned a value.delete arr[7]
          console.log(arr.every((it) => it >= 0)) // true

          代碼

          Array.prototype.every2 = function (callback, thisCtx) {  if (typeof callback !== 'function') {    throw `${callback} is not a function`  }
          const length = this.length let i = 0 // If the length of the array is 0, the while loop will not be entered while (i < length) { // False will be returned as long as a value does not conform to the judgment of callback if (this.hasOwnProperty(i) && !callback.call(thisCtx, this[ i ], i, this)) { return false }
          i++ }
          return true}
          測試一下
          let emptyArr = []// Calling every method on an empty array returns trueconsole.log(emptyArr.every2((it) => it > 0)) // true// The `callback` method will only be called by an index that has already been assigned a value.let arr = [ 0, 1, 2, 3, 4,, 5, -1 ]// The `callback` method will not be called when an array value is deleted or an index that has never been assigned a value.delete arr[7]
          console.log(arr.every2((it) => it >= 0)) // true

          4、some

           some() 方法測試數(shù)組中的至少一個元素是否通過了提供的函數(shù)實現(xiàn)的測試。

          代碼

          Array.prototype.some2 = function (callback, thisCtx) {  if (typeof callback !== 'function') {    throw `${callback} is not a function`  }
          const length = this.length let i = 0
          while (i < length) { // Returns true if any element meets the callback condition if (this.hasOwnProperty(i) && callback.call(thisCtx, this[ i ], i, this)) { return true }
          i++ }
          return false}
          測試一下
          let emptyArr = []// An empty array will return falseconsole.log(emptyArr.some2((it) => it > 0)) // false
          let arr = [ 0, 1, 2, 3, 4,, 5, -1 ]
          delete arr[7]
          console.log(arr.some2((it) => it < 0)) // falseconsole.log(arr.some2((it) => it > 0)) // true

          5、filter

           filter() 方法創(chuàng)建一個新數(shù)組,其中包含所有通過所提供函數(shù)實現(xiàn)的測試的元素。

          Array.prototype.filter2 = function (callback, thisCtx) {  if (typeof callback !== 'function') {    throw `${callback} is not a function`  }
          const length = this.length // The return value will be a new array let newArray = [] let i = 0
          while (i < length) { if (this.hasOwnProperty(i) && callback.call(thisCtx, this[ i ], i, this)) { newArray.push(this[ i ]) } i++ }
          return newArray}
          測試一下
          // The position with index 5 will not be traversed because it has no initialization valuelet arr = [ 0, 1, 2, -3, 4,, 5 ]// we try to remove the last elementdelete arr[6]// filter out values greater than 0let filterArr = arr.filter2((it) => it > 0)
          console.log(filterArr) // [ 1, 2, 4 ]

          6、reduce

          這個函數(shù)稍微復(fù)雜一些。讓我們用一個例子來看看它是如何使用的。

          const sum = [1, 2, 3, 4].reduce((prev, cur) => {  return prev + cur;})
          console.log(sum) // 10
          // initializationprev = initialValue = 1, cur = 2
          // step 1prev = (1 + 2) = 3, cur = 3
          // step 2prev = (3 + 3) = 6, cur = 4
          // step 3prev = (6 + 4) = 10, cur = undefined (quit)

          代碼

          Array.prototype.reduce2 = function (callback, initValue) {  if (typeof callback !== 'function') {    throw `${callback} is not a function`  }
          let pre = initValue let i = 0 const length = this.length // When the initial value is not passed, use the first value of the array as the initial value if (typeof pre === 'undefined') { pre = this[0] i = 1 }
          while (i < length) { if (this.hasOwnProperty(i)) { pre = callback(pre, this[ i ], i, this) } i++ }
          return pre}
          測試一下
          const sum = [1, 2, 3, 4].reduce2((prev, cur) => {  return prev + cur;})console.log(sum) // 10
          7、reduceRight
          reduceRight() 方法對累加器和數(shù)組的每個值(從右到左)應(yīng)用一個函數(shù),以將其減少為單個值。
          它與 reduce 非常相似,只是 reduceRight 從右到左遍歷。
          const sum = [1, 2, 3, 4].reduce((prev, cur) => {  console.log(prev, cur)  return prev + cur;})// 1 2// 3 3// 6 4
          console.log(sum) // 10const sum2 = [1, 2, 3, 4].reduceRight((prev, cur) => { console.log(cur) return prev + cur;})// 4 3// 7 2// 9 1console.log(sum2) // 10

          代碼

          Array.prototype.reduceRight2 = function (callback, initValue) {  if (typeof callback !== 'function') {    throw `${callback} is not a function`  }  let pre = initValue  const length = this.length  // Start with the last element  let i = length - 1  // If no initial value is passed, the last element is taken as the initial value  if (typeof pre === 'undefined') {    pre = this[i]    i--  }  while (i >= 0) {    if (this.hasOwnProperty(i)) {      pre = callback(pre, this[ i ], i, this)    }    i--  }  return pre}

          測試一下

          const sum = [1, 2, 3, 4].reduceRight2((prev, cur) => {  console.log(cur)  return prev + cur;})// 4 3// 7 2// 9 1console.log(sum) // 10

          8、find

          find() 方法返回提供的數(shù)組中滿足提供的測試功能的第一個元素。如果沒有值滿足測試函數(shù),則返回 undefined。

          代碼

          Array.prototype.find2 = function (callback, thisCtx) {  if (typeof callback !== 'function') {    throw `${callback} is not a function`  }  const length = this.length  let i = 0  while (i < length) {    const value = this[ i ]    // As long as there is an element that matches the logic of the callback function, the element value is returned    if (callback.call(thisCtx, value, i, this)) {      return value    }    i++  }  // otherwise return undefined    return undefined}
          測試一下
          let arr = [ 0, 1, 2, 3, 4,, 5 ]let ele = arr.find2(function (it, i, array) {  console.log(it, i, array, this)  return it > 3}, { name: 'fatfish' })console.log(ele) // 4

          9、findIndex

          findIndex() 方法返回數(shù)組中滿足提供的測試函數(shù)的第一個元素的索引。否則,它返回 -1,表示沒有元素通過測試。

          let arr = [ 0, 1, 2, 3, 4,, 5 ]let index = arr.findIndex((it, i, array) => {  return it > 2})console.log(index) // 3
          代碼
          Array.prototype.findIndex2 = function (callback, thisCtx) {  if (typeof callback !== 'function') {    throw `${callback} is not a function`  }  const length = this.length  let i = 0  while (i < length) {    // Return index i that conforms to callback logic    if (callback.call(thisCtx, this[ i ], i, this)) {      return i    }    i++  }  return -1}
          測試一下
          let arr = [ 0, 1, 2, 3, 4,, 5 ]let index = arr.findIndex2(function (it, i, array) {  console.log(it, i, array, this)  return it > 2}, { name: 'fatfish' })console.log(index) // 3
          10、indexOf
          indexOf() 方法返回可以在數(shù)組中找到給定元素的第一個索引,如果不存在,則返回 -1。
          筆記:
          如果開始搜索的索引值大于等于數(shù)組的長度,則表示不會在數(shù)組中進(jìn)行搜索,返回-1。
          如果fromIndex為負(fù)數(shù),則按照-1表示從最后一個元素開始查找,-2表示從倒數(shù)第二個元素開始查找的規(guī)則進(jìn)行查找,以此類推。
          如果 fromIndex 為負(fù)數(shù),則仍然從前向后搜索數(shù)組。
          const array = [2, 5, 9]console.log(array.indexOf(2))      // 0console.log(array.indexOf(7))      // -1console.log(array.indexOf(9, 2))   // 2console.log(array.indexOf(2, -1))  // -1console.log(array.indexOf(2, -3))  // 0console.log(array.indexOf(2, -4))  // 0

          代碼

          Array.prototype.indexOf2 = function (targetEle, fromIndex) {  const length = this.length  fromIndex = +fromIndex || 0  // If the array is empty or the search starts from a place greater than or equal to the length of the array, it will directly return -1  if (length === 0 || fromIndex >= length) {    return -1  }  /*    1. Search elements from fromIndex    2. Use it directly when fromindex is greater than 0    3. If it is less than 0, first subtract the absolute value of fromIndex from the length. If it is still less than 0, take 0 directly  */  let i = Math.max(fromIndex >= 0 ? fromIndex : length - Math.abs(fromIndex), 0)  while (i < length) {    // element in the array and equal to targetEle    if (this.hasOwnProperty(i) && targetEle === this[ i ]) {      return i    }    i++  }  return -1}

          測試一下

          const array = [2, 5, 9]console.log(array.indexOf2(2))      // 0console.log(array.indexOf2(7))      // -1console.log(array.indexOf2(9, 2))   // 2console.log(array.indexOf2(2, -1))  // -1console.log(array.indexOf2(2, -3))  // 0console.log(array.indexOf2(2, -4))  // 0
          11、lastIndexOf
          lastIndexOf() 方法返回可以在數(shù)組中找到給定元素的最后一個索引,如果不存在,則返回 -1。從 fromIndex 開始向后搜索數(shù)組。
          它與 indexOf 非常相似,只是 lastIndexOf 從右到左遍歷。
          let array = [2, 5, 9, 2]console.log(array.lastIndexOf(2)) // 3console.log(array.lastIndexOf(7)) // -1console.log(array.lastIndexOf(2, 3)) // 3console.log(array.lastIndexOf(2, 2)) // 0console.log(array.lastIndexOf(2, -2)) // 0console.log(array.lastIndexOf(2, -1)) // 3
          代碼
          Array.prototype.lastIndexOf2 = function (targetEle, fromIndex) {  const length = this.length  fromIndex = typeof fromIndex === 'undefined' ? length - 1 : fromIndex  // // Empty array, when fromIndex is negative and the absolute value is greater than the length of the array, the method returns -1, that is, the array will not be searched.  if (length === 0 || fromIndex < 0 && Math.abs(fromIndex) >= length) {    return -1  }  let i  if (fromIndex >= 0) {    // If `fromIndex` is greater than or equal to the length of the array, the entire array is searched.    i = Math.min(fromIndex, length - 1)  } else {    i = length - Math.abs(fromIndex)  }  while (i >= 0) {    // Returns the index when it is equal to targetEle    if (i in this && targetEle === this[ i ]) {      return i    }    i--  }  // Returns -1 when the current value is not found  return -1}
          測試一下
          let array = [2, 5, 9, 2]console.log(array.lastIndexOf2(2)) // 3console.log(array.lastIndexOf2(7)) // -1console.log(array.lastIndexOf2(2, 3)) // 3console.log(array.lastIndexOf2(2, 2)) // 0console.log(array.lastIndexOf2(2, -2)) // 0console.log(array.lastIndexOf2(2, -1)) // 3

          12、includes

          includes() 方法確定數(shù)組是否在其條目中包含某個值,根據(jù)需要返回 true 或 false。

          arr.includes(valueToFind[, fromIndex])
          筆記
          include 方法將從 fromIndex 索引開始搜索 valueToFind。
          如果 fromIndex 為負(fù)數(shù),則開始搜索 array.length + fromIndex 的索引。
          如果數(shù)組中存在 NaN,則 [..., NaN] Includes (NaN) 為真。
          console.log([1, 2, 3].includes(2))     // trueconsole.log([1, 2, 3].includes(4))     // falseconsole.log([1, 2, 3].includes(3, 3))  // falseconsole.log([1, 2, 3].includes(3, -1)) // trueconsole.log([1, 2, NaN].includes(NaN)) // true

          代碼

          Array.prototype.includes2 = function (targetEle, fromIndex) {  const length = this.length  fromIndex = +fromIndex || 0  if (length === 0 || fromIndex >= length) {    return false  }  // Search for elements from the position of fromIndex  let i = Math.max(fromIndex >= 0 ? fromIndex : length - Math.abs(fromIndex), 0)  while (i < length) {    const value = this[ i ]    // Please note NaN    if (targetEle === value || typeof targetEle === 'number' && typeof value === 'number' && isNaN(targetEle) && isNaN(value)) {      return true    }    i++  }  return false}
          測試一下
          console.log([1, 2, 3].includes2(2))     // trueconsole.log([1, 2, 3].includes2(4))     // falseconsole.log([1, 2, 3].includes2(3, 3))  // falseconsole.log([1, 2, 3].includes2(3, -1)) // trueconsole.log([1, 2, NaN].includes2(NaN)) // true
          13、push
          push() 方法將一個或多個元素添加到數(shù)組的末尾,并返回數(shù)組的新長度。
          const animals = ['pigs', 'goats', 'sheep']animals.push('cows')console.log(animals, animals.length) // ["pigs", "goats", "sheep", "cows"], 4animals.push('chickens', 'cats', 'dogs')console.log(animals, animals.length) // ["pigs", "goats", "sheep", "cows", "chickens", "cats", "dogs"], 7
          代碼
          Array.prototype.push2 = function (...pushEles) {  const pushEleLength = pushEles.length  const length = this.length  let i = 0
          while (i < pushEleLength) { this[ length + i ] = pushEles[ i ] i++ } return this.length}

          測試一下

          const animals = ['pigs', 'goats', 'sheep']animals.push2('cows')console.log(animals, animals.length) // ["pigs", "goats", "sheep", "cows"], 4animals.push2('chickens', 'cats', 'dogs')console.log(animals, animals.length) // ["pigs", "goats", "sheep", "cows", "chickens", "cats", "dogs"], 7
          14、pop
          pop() 方法從數(shù)組中刪除最后一個元素并返回該元素,此方法更改數(shù)組的長度。
          let arr = [ 1, 2 ]let arr2 = []console.log(arr.pop(), arr) // 2 [1]console.log(arr2.pop(), arr2) // undefined []
          代碼
          Array.prototype.pop2 = function () {  const length = this.length  // If it is an empty array, return undefined  if (length === 0) {    return undefined  }  const delEle = this[ length - 1 ]  this.length = length - 1  return delEle}
          測試一下
          let arr = [ 1, 2 ]let arr2 = []console.log(arr.pop2(), arr) // 2 [1]console.log(arr2.pop2(), arr2) // undefined []
          15、unshift
          unshift() 方法將一個或多個元素添加到數(shù)組的開頭并返回數(shù)組的新長度。
          筆記
          如果傳入多個參數(shù)調(diào)用 unshift 一次,與傳入一個參數(shù)調(diào)用 unshift 多次(例如循環(huán)調(diào)用)會得到不同的結(jié)果。
          let arr = [4,5,6]// Insert multiple elements at oncearr.unshift(1,2,3)console.log(arr) // [1, 2, 3, 4, 5, 6]let arr2 = [4,5,6]// Insert multiple timesarr2.unshift(1)arr2.unshift(2)arr2.unshift(3)console.log(arr2); // [3, 2, 1, 4, 5, 6]
          代碼
          Array.prototype.unshift2 = function (...unshiftEles) {  // With "...", Insert the element to be added in front of the array  let newArray = [ ...unshiftEles, ...this ]  let length = newArray.length
          let i = 0 if (unshiftEles.length === 0) { return length } // Recopy to array while (i < length) { this[ i ] = newArray[ i ] i++ }
          return this.length}
          測試一下
          let arr = [4,5,6]// Insert multiple elements at oncearr.unshift2(1,2,3)console.log(arr) // [1, 2, 3, 4, 5, 6]let arr2 = [4,5,6]// Insert multiple timesarr2.unshift2(1)arr2.unshift2(2)arr2.unshift2(3)console.log(arr2); // [3, 2, 1, 4, 5, 6]
          16、 shift
          shift() 方法從數(shù)組中刪除第一個元素并返回該刪除的元素。此方法更改數(shù)組的長度。
          let arr = [ 1, 2 ]console.log(arr.shift(), arr) // 1 [2]console.log(arr.shift(), arr) // 2 []

          代碼

          Array.prototype.shift2 = function () {  const length = this.length  const delValue = this[ 0 ]  let i = 1  while (i < length) {    // Starting from the first element, the following elements move forward one bit    this[ i - 1 ] = this[ i ]    i++  }  // Set the length of the array  this.length = length - 1  // Return deleted value  return delValue}
          測試一下
          let arr = [ 1, 2 ]console.log(arr.shift2(), arr) // 1 [2]console.log(arr.shift2(), arr) // 2 []

          17、reverse

          (來自 MDN) reverse() 方法將數(shù)組反轉(zhuǎn)到位。第一個數(shù)組元素成為最后一個,最后一個數(shù)組元素成為第一個。

          const arr = [1, 2, 3]console.log(arr) // [1, 2, 3]arr.reverse()console.log(arr) // [3, 2, 1]
          代碼
          Array.prototype.reverse2 = function () {  let i = 0  let j = this.length - 1  while (i < j) {    [ this[ i ], this[ j ] ] = [ this[ j ], this[ i ] ]    i++    j--  }  return this}
          測試一下
          const arr = [1, 2, 3]console.log(arr) // [1, 2, 3]arr.reverse2()console.log(arr) // [3, 2, 1]

          18、fill

          fill() 方法將數(shù)組中的所有元素更改為靜態(tài)值,從開始索引(默認(rèn) 0)到結(jié)束索引(默認(rèn) array.length),它返回修改后的數(shù)組。
          const array1 = [1, 2, 3, 4];console.log(array1.fill(0, 2, 4)) // [1, 2, 0, 0]
          console.log(array1.fill(5, 1)) // [1, 5, 5, 5]console.log(array1.fill(6)) // [6, 6, 6, 6]
          代碼
          Array.prototype.fill2 = function (value, start, end) {  const length = this.length  start = start >> 0  // The default value of end is length  end = typeof end === 'undefined' ? length : end >> 0  // The minimum value of start is 0 and the maximum value is length  start = start >= 0 ? Math.min(start, length) : Math.max(start + length, 0)  // The minimum value of end is 0 and the maximum value is length  end = end >= 0 ? Math.min(end, length) : Math.max(end + length, 0)  // The element that fills the specified range is value  while (start < end) {    this[ start ] = value    start++  }  return this}
          測試一下
          const array1 = [1, 2, 3, 4];console.log(array1.fill2(0, 2, 4)) // [1, 2, 0, 0]
          console.log(array1.fill2(5, 1)) // [1, 5, 5, 5]console.log(array1.fill2(6)) // [6, 6, 6, 6]
          19、concat
          concat() 方法用于合并兩個或多個數(shù)組。此方法不會更改現(xiàn)有數(shù)組,而是返回一個新數(shù)組。
          let num1 = [[1]]let num2 = [2, [3]]let num3=[5,[6]]let nums = num1.concat(num2) // [[1], 2, [3]]let nums2 = num1.concat(4, num3) // [[1], 4, 5,[6]]

          代碼

          Array.prototype.concat2 = function (...concatEles) {  const length = concatEles.length  // The array itself needs to be expanded one layer  let newArray = [ ...this ]  let i = 0  while (i < length) {    const value = concatEles[ i ]    Array.isArray(value) ? newArray.push(...value) : newArray.push(value)    i++  }  return newArray}

          測試一下

          let num1 = [[1]]let num2 = [2, [3]]let num3=[5,[6]]let nums = num1.concat2(num2) // [[1], 2, [3]]let nums2 = num1.concat2(4, num3) // [[1], 4, 5,[6]]
          20、join
          join() 方法通過連接數(shù)組(或類似數(shù)組的對象)中的所有元素創(chuàng)建并返回一個新字符串,用逗號或指定的分隔符字符串分隔。如果數(shù)組只有一個項目,則將返回該項目而不使用分隔符。
          const elements = ['Fire', 'Air', 'Water']const elements2 = ['Fire']console.log(elements.join()) // Fire,Air,Waterconsole.log(elements.join('')) // FireAirWaterconsole.log(elements.join('-')) //  Fire-Air-Waterconsole.log(elements2.join('-')) // Fire

          代碼

          Array.prototype.join2 = function (format = ',') {  const length = this.length  // Save the last element because it does not participate in the connection of format  let lastEle = this[ length - 1 ]  let string = ''  if (length === 0) {    return string  }  for (i = 0; i < length - 1; i++) {    string += this[ i ] + format  }  return string + lastEle}

          測試一下

          const elements = ['Fire', 'Air', 'Water']const elements2 = ['Fire']console.log(elements.join2()) // Fire,Air,Waterconsole.log(elements.join2('')) // FireAirWaterconsole.log(elements.join2('-')) //  Fire-Air-Waterconsole.log(elements2.join2('-')) // Fire
          最后
          以上就是我今天跟你分享的20個數(shù)組方法的實現(xiàn),希望對你有用,如果你覺得有幫助的話,請記得點贊我,關(guān)注我,并將他分享給你身邊做開發(fā)的朋友。
          最后,感謝你的閱讀,期待你的關(guān)注,我將分享更多優(yōu)質(zhì)文章內(nèi)容。


          學(xué)習(xí)更多技能

          請點擊下方公眾號

          瀏覽 43
          點贊
          評論
          收藏
          分享

          手機掃一掃分享

          分享
          舉報
          評論
          圖片
          表情
          推薦
          點贊
          評論
          收藏
          分享

          手機掃一掃分享

          分享
          舉報
          <kbd id="afajh"><form id="afajh"></form></kbd>
          <strong id="afajh"><dl id="afajh"></dl></strong>
            <del id="afajh"><form id="afajh"></form></del>
                1. <th id="afajh"><progress id="afajh"></progress></th>
                  <b id="afajh"><abbr id="afajh"></abbr></b>
                  <th id="afajh"><progress id="afajh"></progress></th>
                  国产黄色视频免费看 | 亚洲日韩人妻蜜臀专区无码 | 五月丁香色婷 | 北条麻妃一区在线 | 无码性爱视频在线观看 |