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          C++核心準則ES.102:使用有符號數(shù)進行數(shù)學運算

          50f00d60d7d9cc76425b45ebab590b1d.webp

          ES.102: Use signed types for arithmetic

          ES.102:使用有符號數(shù)進行數(shù)學運算


          Reason(原因)

          Because most arithmetic is assumed to be signed;?x - y?yields a negative number when?y > x?except in the rare cases where you really want modulo arithmetic.

          因為大部分數(shù)學運算都是有符號的。當x>y時,x-y會返回一個負數(shù),極少情況實際需要的是按模運算。


          Example(示例)

          Unsigned arithmetic can yield surprising results if you are not expecting it. This is even more true for mixed signed and unsigned arithmetic.

          如果不是你有意為之,無符號運算可能產(chǎn)生意外的結(jié)果。如果混用有符號數(shù)和無符號數(shù),問題會更明顯。

          template
          T subtract(T x, T2 y)
          {
          return x - y;
          }

          void test()
          {
          int s = 5;
          unsigned int us = 5;
          cout << subtract(s, 7) << '\n'; // -2
          cout << subtract(us, 7u) << '\n'; // 4294967294
          cout << subtract(s, 7u) << '\n'; // -2
          cout << subtract(us, 7) << '\n'; // 4294967294
          cout << subtract(s, us + 2) << '\n'; // -2
          cout << subtract(us, s + 2) << '\n'; // 4294967294
          }

          Here we have been very explicit about what's happening, but if you had seen?us - (s + 2)?or?s += 2; ...; us - s, would you reliably have suspected that the result would print as?4294967294?

          代碼中我們已經(jīng)很明確地知道發(fā)生了什么。但是如果你看到us - (s + 2) or s += 2; ...; us - s,你真的可以想象結(jié)果是4294967294么?


          Exception(例外)

          Use unsigned types if you really want modulo arithmetic - add comments as necessary noting the reliance on overflow behavior, as such code is going to be surprising for many programmers.

          如果你真的需要按模運算-增加必要的注釋提示對溢出行為的依賴,這樣的代碼會令很多程序員疑惑。


          Example(示例)

          The standard library uses unsigned types for subscripts. The built-in array uses signed types for subscripts. This makes surprises (and bugs) inevitable.

          標準庫使用無符號類型作為下標。內(nèi)置數(shù)組使用有符號數(shù)作為下標。這會導致代碼難于理解并不可避免地帶來錯誤。

          int a[10];
          for (int i = 0; i < 10; ++i) a[i] = i;
          vector v(10);
          // compares signed to unsigned; some compilers warn, but we should not
          for (gsl::index i = 0; i < v.size(); ++i) v[i] = i;

          int a2[-2]; // error: negative size

          // OK, but the number of ints (4294967294) is so large that we should get an exception
          vector v2(-2);

          Use?gsl::index?for subscripts;?see ES.107.

          使用ES.107中介紹的gsl::index作為下標。


          Enforcement(實施建議)

          • Flag mixed signed and unsigned arithmetic

          • 標記有符號數(shù)和無符號數(shù)混用的數(shù)學運算。

          • Flag results of unsigned arithmetic assigned to or printed as signed.

          • 標記將無符號數(shù)學運算的結(jié)果賦值給有符號數(shù)或者作為有符號數(shù)print輸出的情況。

          • Flag negative literals (e.g.?-2) used as container subscripts.

          • 標記使用負值作為容器下標的情況。

          • (To avoid noise) Do not flag on a mixed signed/unsigned comparison where one of the arguments is?sizeof?or a call to container?.size()?and the other is?ptrdiff_t.

          • (為了避免誤判)當一個參數(shù)是sizeof或者container.size()的返回值,而另一個參數(shù)是ptrdiff_t的時候,不要標記有符號數(shù)/無符號數(shù)混合的比較操作。


          原文鏈接

          https://github.com/isocpp/CppCoreGuidelines/blob/master/CppCoreGuidelines.md#es102-use-signed-types-for-arithmetic




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