C++核心準(zhǔn)則C.63:保證移動(dòng)賦值運(yùn)算符為非虛函數(shù),參數(shù)類型為右值...

C.63: Make move assignment non-virtual, take the parameter by &&, and return by non-const &
C.63:保證移動(dòng)賦值運(yùn)算符為非虛函數(shù)，參數(shù)類型為右值引用，返回值為常量引用類型

Reason（原因）

It is simple and efficient.

這樣做簡(jiǎn)單且高效。

See（參見）:

The rule for copy-assignment.

拷貝賦值規(guī)則。

相關(guān)鏈接：

https://github.com/isocpp/CppCoreGuidelines/blob/master/CppCoreGuidelines.md#Rc-copy-assignment

Enforcement（實(shí)施建議）

Equivalent to what is done for copy-assignment.

和拷貝賦值的情況時(shí)所做的相同。

• (Simple) An assignment operator should not be virtual. Here be dragons!

  （簡(jiǎn)單）賦值運(yùn)算符不應(yīng)該是虛函數(shù)。那樣做很危險(xiǎn)。
  

• (Simple) An assignment operator should return T& to enable chaining, not alternatives like const T& which interfere with composability and putting objects in containers.

  （簡(jiǎn)單）賦值運(yùn)算符應(yīng)該返回T&，這樣才能實(shí)現(xiàn)連續(xù)賦值。不要改成類似const T&的類型，這樣會(huì)影響組裝性并妨礙將對(duì)象放進(jìn)容器中。

• (Moderate) A move assignment operator should (implicitly or explicitly) invoke all base and member move assignment operators.

  （中等）移動(dòng)賦值運(yùn)算符應(yīng)該（隱式或顯式）調(diào)用所有的基類和成員的移動(dòng)賦值運(yùn)算符。

原文鏈接

https://github.com/isocpp/CppCoreGuidelines/blob/master/CppCoreGuidelines.md#c63-make-move-assignment-non-virtual-take-the-parameter-by--and-return-by-non-const-

---

覺得本文有幫助？請(qǐng)分享給更多人。

關(guān)注【面向?qū)ο笏伎肌枯p松學(xué)習(xí)每一天！

面向?qū)ο箝_發(fā)，面向?qū)ο笏伎迹?/span>