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          手把手教你實現(xiàn)一個抽獎系統(tǒng)(Java版)

          共 4279字,需瀏覽 9分鐘

           ·

          2021-12-25 04:37

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          優(yōu)質(zhì)文章,第一時間送達(dá)


          -? ?1 概述? ? -

          項目開發(fā)中經(jīng)常會有抽獎這樣的營銷活動的需求,例如:積分大轉(zhuǎn)盤、刮刮樂、老虎機(jī)等等多種形式,其實后臺的實現(xiàn)方法是一樣的,本文介紹一種常用的抽獎實現(xiàn)方法。

          整個抽獎過程包括以下幾個方面:

          1. 獎品

          2. 獎品池

          3. 抽獎算法

          4. 獎品限制

          5. 獎品發(fā)放



          -? ?2 獎品? ? -

          獎品包括獎品、獎品概率和限制、獎品記錄。
          獎品表:

          CREATE?TABLE?`points_luck_draw_prize`?(
          ??`id`?bigint(20)?NOT?NULL?AUTO_INCREMENT,
          ??`name`?varchar(50)?DEFAULT?NULL?COMMENT?'獎品名稱',
          ??`url`?varchar(50)?DEFAULT?NULL?COMMENT?'圖片地址',
          ??`value`?varchar(20)?DEFAULT?NULL,
          ??`type`?tinyint(4)?DEFAULT?NULL?COMMENT?'類型1:紅包2:積分3:體驗金4:謝謝惠顧5:自定義',
          ??`status`?tinyint(4)?DEFAULT?NULL?COMMENT?'狀態(tài)',
          ??`is_del`?bit(1)?DEFAULT?NULL?COMMENT?'是否刪除',
          ??`position`?int(5)?DEFAULT?NULL?COMMENT?'位置',
          ??`phase`?int(10)?DEFAULT?NULL?COMMENT?'期數(shù)',
          ??`create_time`?datetime?DEFAULT?NULL,
          ??`update_time`?datetime?DEFAULT?NULL,
          ??PRIMARY?KEY?(`id`)
          )?ENGINE=InnoDB?AUTO_INCREMENT=164?DEFAULT?CHARSET=utf8mb4?COMMENT='獎品表';

          獎品概率限制表:

          CREATE?TABLE?`points_luck_draw_probability`?(
          ??`id`?bigint(20)?NOT?NULL?AUTO_INCREMENT,
          ??`points_prize_id`?bigint(20)?DEFAULT?NULL?COMMENT?'獎品ID',
          ??`points_prize_phase`?int(10)?DEFAULT?NULL?COMMENT?'獎品期數(shù)',
          ??`probability`?float(4,2)?DEFAULT?NULL?COMMENT?'概率',
          ??`frozen`?int(11)?DEFAULT?NULL?COMMENT?'商品抽中后的冷凍次數(shù)',
          ??`prize_day_max_times`?int(11)?DEFAULT?NULL?COMMENT?'該商品平臺每天最多抽中的次數(shù)',
          ??`user_prize_month_max_times`?int(11)?DEFAULT?NULL?COMMENT?'每位用戶每月最多抽中該商品的次數(shù)',
          ??`create_time`?datetime?DEFAULT?NULL,
          ??`update_time`?datetime?DEFAULT?NULL,
          ??PRIMARY?KEY?(`id`)
          )?ENGINE=InnoDB?AUTO_INCREMENT=114?DEFAULT?CHARSET=utf8mb4?COMMENT='抽獎概率限制表';

          獎品記錄表:

          CREATE?TABLE?`points_luck_draw_record`?(
          ??`id`?bigint(20)?NOT?NULL?AUTO_INCREMENT,
          ??`member_id`?bigint(20)?DEFAULT?NULL?COMMENT?'用戶ID',
          ??`member_mobile`?varchar(11)?DEFAULT?NULL?COMMENT?'中獎用戶手機(jī)號',
          ??`points`?int(11)?DEFAULT?NULL?COMMENT?'消耗積分',
          ??`prize_id`?bigint(20)?DEFAULT?NULL?COMMENT?'獎品ID',
          ??`result`?smallint(4)?DEFAULT?NULL?COMMENT?'1:中獎?2:未中獎',
          ??`month`?varchar(10)?DEFAULT?NULL?COMMENT?'中獎月份',
          ??`daily`?date?DEFAULT?NULL?COMMENT?'中獎日期(不包括時間)',
          ??`create_time`?datetime?DEFAULT?NULL,
          ??`update_time`?datetime?DEFAULT?NULL,
          ??PRIMARY?KEY?(`id`)
          )?ENGINE=InnoDB?AUTO_INCREMENT=3078?DEFAULT?CHARSET=utf8mb4?COMMENT='抽獎記錄表';



          -? ?3 獎品池? ? -

          獎品池是根據(jù)獎品的概率和限制組裝成的抽獎用的池子。主要包括獎品的總池值和每個獎品所占的池值(分為開始值和結(jié)束值)兩個維度。

          • 獎品的總池值:所有獎品池值的總和。

          • 每個獎品的池值:算法可以變通,常用的有以下兩種方式 :

            1. 獎品的概率*10000(保證是整數(shù))

            2. 獎品的概率10000獎品的剩余數(shù)量

          獎品池bean:

          public?class?PrizePool?implements?Serializable{
          ????/**
          ?????*?總池值
          ?????*/
          ????private?int?total;
          ????/**
          ?????*?池中的獎品
          ?????*/
          ????private?List?poolBeanList;
          }

          池中的獎品bean:

          public?class?PrizePoolBean?implements?Serializable{
          ????/**
          ?????*?數(shù)據(jù)庫中真實獎品的ID
          ?????*/
          ????private?Long?id;
          ????/**
          ?????*?獎品的開始池值
          ?????*/
          ????private?int?begin;
          ????/**
          ?????*?獎品的結(jié)束池值
          ?????*/
          ????private?int?end;
          }

          獎品池的組裝代碼:

          /**
          ?????*?獲取超級大富翁的獎品池
          ?????*?@param?zillionaireProductMap?超級大富翁獎品map
          ?????*?@param?flag?true:有現(xiàn)金??false:無現(xiàn)金
          ?????*?@return
          ?????*/
          ????private?PrizePool?getZillionairePrizePool(Map?zillionaireProductMap,?boolean?flag)?{
          ????????//總的獎品池值
          ????????int?total?=?0;
          ????????List?poolBeanList?=?new?ArrayList<>();
          ????????for(Entry?entry?:?zillionaireProductMap.entrySet()){
          ????????????ActivityProduct?product?=?entry.getValue();
          ????????????//無現(xiàn)金獎品池,過濾掉類型為現(xiàn)金的獎品
          ????????????if(!flag?&&?product.getCategoryId()?==?ActivityPrizeTypeEnums.XJ.getType()){
          ????????????????continue;
          ????????????}
          ????????????//組裝獎品池獎品
          ????????????PrizePoolBean?prizePoolBean?=?new?PrizePoolBean();
          ????????????prizePoolBean.setId(product.getProductDescriptionId());
          ????????????prizePoolBean.setBengin(total);
          ????????????total?=?total?+?product.getEarnings().multiply(new?BigDecimal("10000")).intValue();
          ????????????prizePoolBean.setEnd(total);
          ????????????poolBeanList.add(prizePoolBean);
          ????????}

          ????????PrizePool?prizePool?=?new?PrizePool();
          ????????prizePool.setTotal(total);
          ????????prizePool.setPoolBeanList(poolBeanList);
          ????????return?prizePool;
          ????}



          -? ?4 抽獎算法? ? -

          整個抽獎算法為:

          1.?隨機(jī)獎品池總池值以內(nèi)的整數(shù)?
          2. 循環(huán)比較獎品池中的所有獎品,隨機(jī)數(shù)落到哪個獎品的池區(qū)間即為哪個獎品中獎。

          抽獎代碼:

          public?static?PrizePoolBean?getPrize(PrizePool?prizePool){
          ????????//獲取總的獎品池值
          ????????int?total?=?prizePool.getTotal();
          ????????//獲取隨機(jī)數(shù)
          ????????Random?rand=new?Random();
          ????????int?random=rand.nextInt(total);
          ????????//循環(huán)比較獎品池區(qū)間
          ????????for(PrizePoolBean?prizePoolBean?:?prizePool.getPoolBeanList()){
          ????????????if(random?>=?prizePoolBean.getBengin()?&&?random?????????????????return?prizePoolBean;
          ????????????}
          ????????}
          ????????return?null;
          ????}



          -? ?5 獎品限制? ? -

          實際抽獎中對一些比較大的獎品往往有數(shù)量限制,比如:某某獎品一天最多被抽中5次、某某獎品每位用戶只能抽中一次。。等等類似的限制,對于這樣的限制我們分為兩種情況來區(qū)別對待:

          1. 限制的獎品比較少,通常不多于3個:這種情況我們可以再組裝獎品池的時候就把不符合條件的獎品過濾掉,這樣抽中的獎品都是符合條件的。例如,在上面的超級大富翁抽獎代碼中,我們規(guī)定現(xiàn)金獎品一天只能被抽中5次,那么我們可以根據(jù)判斷條件分別組裝出有現(xiàn)金的獎品和沒有現(xiàn)金的獎品。
          2. 限制的獎品比較多,這樣如果要采用第一種方式,就會導(dǎo)致組裝獎品非常繁瑣,性能低下,我們可以采用抽中獎品后校驗抽中的獎品是否符合條件,如果不符合條件則返回一個固定的獎品即可。



          -? ?6 獎品發(fā)放? ? -

          獎品發(fā)放可以采用工廠模式進(jìn)行發(fā)放:不同的獎品類型走不同的獎品發(fā)放處理器,示例代碼如下:
          獎品發(fā)放:

          /**
          ?????*?異步分發(fā)獎品
          ?????*?@param?prizeList
          ?????*?@throws?Exception
          ?????*/
          ????@Async("myAsync")
          ????@Transactional(rollbackFor?=?Exception.class,?propagation?=?Propagation.REQUIRED)
          ????public?Future?sendPrize(Long?memberId,?List?prizeList){
          ????????try?{
          ????????????for(PrizeDto?prizeDto?:?prizeList){
          ????????????????//過濾掉謝謝惠顧的獎品
          ????????????????if(prizeDto.getType()?==?PointsLuckDrawTypeEnum.XXHG.getType()){
          ????????????????????continue;
          ????????????????}
          ????????????????//根據(jù)獎品類型從工廠中獲取獎品發(fā)放類
          ????????????????SendPrizeProcessor?sendPrizeProcessor?=?sendPrizeProcessorFactory.getSendPrizeProcessor(
          ????????????????????PointsLuckDrawTypeEnum.getPointsLuckDrawTypeEnumByType(prizeDto.getType()));
          ????????????????if(ObjectUtil.isNotNull(sendPrizeProcessor)){
          ????????????????????//發(fā)放獎品
          ????????????????????sendPrizeProcessor.send(memberId,?prizeDto);
          ????????????????}
          ????????????}
          ????????????return?new?AsyncResult<>(Boolean.TRUE);
          ????????}catch?(Exception?e){
          ????????????//獎品發(fā)放失敗則記錄日志
          ????????????saveSendPrizeErrorLog(memberId,?prizeList);
          ????????????LOGGER.error("積分抽獎發(fā)放獎品出現(xiàn)異常",?e);
          ????????????return?new?AsyncResult<>(Boolean.FALSE);
          ????????}
          ????}

          工廠類:

          @Component
          public?class?SendPrizeProcessorFactory?implements?ApplicationContextAware{
          ????private?ApplicationContext?applicationContext;

          ????@Override
          ????public?void?setApplicationContext(ApplicationContext?applicationContext)?throws?BeansException?{
          ????????this.applicationContext?=?applicationContext;
          ????}

          ????public?SendPrizeProcessor?getSendPrizeProcessor(PointsLuckDrawTypeEnum?typeEnum){
          ????????String?processorName?=?typeEnum.getSendPrizeProcessorName();
          ????????if(StrUtil.isBlank(processorName)){
          ????????????return?null;
          ????????}
          ????????SendPrizeProcessor?processor?=?applicationContext.getBean(processorName,?SendPrizeProcessor.class);
          ????????if(ObjectUtil.isNull(processor)){
          ????????????throw?new?RuntimeException("沒有找到名稱為【"?+?processorName?+?"】的發(fā)送獎品處理器");
          ????????}
          ????????return?processor;
          ????}
          }

          獎品發(fā)放類舉例:

          /**
          ?*?紅包獎品發(fā)放類
          ?*/
          @Component("sendHbPrizeProcessor")
          public?class?SendHbPrizeProcessor?implements?SendPrizeProcessor{
          ????private?Logger?LOGGER?=?LoggerFactory.getLogger(SendHbPrizeProcessor.class);
          ????@Resource
          ????private?CouponService?couponService;
          ????@Resource
          ????private?MessageLogService?messageLogService;

          ????@Override
          ????public?void?send(Long?memberId,?PrizeDto?prizeDto)?throws?Exception?{
          ????????//?發(fā)放紅包
          ????????Coupon?coupon?=?couponService.receiveCoupon(memberId,?Long.parseLong(prizeDto.getValue()));
          ????????//發(fā)送站內(nèi)信
          ????????messageLogService.insertActivityMessageLog(memberId,
          ????????????"你參與積分抽大獎活動抽中的"?+?coupon.getAmount()?+?"元理財紅包已到賬,謝謝參與",
          ????????????"積分抽大獎中獎通知");
          ????????//輸出log日志
          ????????LOGGER.info(memberId?+?"在積分抽獎中抽中的"?+?prizeDto.getPrizeName()?+?"已經(jīng)發(fā)放!");
          ????}
          }



          ? 作者?|??秦霜

          來源 |??csdn.net/wang258533488/article/details/78901303


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