【45期】盤點(diǎn)那些必問(wèn)的數(shù)據(jù)結(jié)構(gòu)算法題之基礎(chǔ)排序
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來(lái)自:juejin.im/post/5bacdd2b5188255c3f6be3c2
0 概述
本文代碼:https://github.com/shishujuan/dsalg/tree/master/code/alg/sort
1 插入排序
/**
?*?插入排序
?*/
void?insertSort(int?a[],?int?n)
{
????int?i,?j;
????for?(i?=?1;?i?????????/*
?????????*?循環(huán)不變式:a[0...i-1]有序。每次迭代開(kāi)始前,a[0...i-1]有序,
?????????*?循環(huán)結(jié)束后i=n,a[0...n-1]有序
?????????*?*/
????????int?key?=?a[i];
????????for?(j?=?i;?j?>?0?&&?a[j-1]?>?key;?j--)?{
????????????a[j]?=?a[j-1];
????????}
????????a[j]?=?key;
????}
}
2 希爾排序
/**
?*?希爾排序
?*/
void?shellSort(int?a[],?int?n)
{
????int?gap;
????for?(gap?=?n/2;?gap?>?0;?gap?/=?2)?{
????????int?i;
????????for?(i?=?gap;?i?????????????int?key?=?a[i],?j;
????????????for?(j?=?i;?j?>=?gap?&&?key?????????????????a[j]?=?a[j-gap];
????????????}
????????????a[j]?=?key;
????????}
????}
}
3 選擇排序
/**
?*?選擇排序
?*/
void?selectSort(int?a[],?int?n)
{
????int?i,?j,?min,?tmp;
????for?(i?=?0;?i?-1;?i++)?{
????????min?=?i;
????????for?(j?=?i+1;?j?????????????if?(a[j]?????????????????min?=?j;
????????}
????????if?(min?!=?i)
????????????tmp?=?a[i],?a[i]?=?a[min],?a[min]?=?tmp;?//交換a[i]和a[min]
????}
}
初始時(shí),i=0,a[0…-1] 為空,顯然成立。
每次執(zhí)行完成后,a[0…i] 包含 a 中最小的 i+1 個(gè)數(shù),且有序。即第一次執(zhí)行完成后,a[0…0] 包含 a 最小的 1 個(gè)數(shù),且有序。
循環(huán)結(jié)束后,i=n-1,則 a[0…n-2]包含 a 最小的 n-1 個(gè)數(shù),且已經(jīng)有序。所以整個(gè)數(shù)組有序。
4 冒泡排序
/**
?*?冒泡排序-經(jīng)典版
?*/
void?bubbleSort(int?a[],?int?n)
{
????int?i,?j,?tmp;
????for?(i?=?0;?i?????????for?(j?=?n-1;?j?>=?i+1;?j--)?{
????????????if?(a[j]?-1])
????????????????tmp?=?a[j],?a[j]?=?a[j-1],?a[j-1]?=?tmp;
????????}
????}
}
/**
?*?冒泡排序-優(yōu)化版
?*/
void?betterBubbleSort(int?a[],?int?n)
{
????int?tmp,?i,?j;
????for?(i?=?0;?i?????????int?sorted?=?1;
????????for?(j?=?n-1;?j?>=?i+1;?j--)?{
????????????if?(a[j]?-1])?{
????????????????tmp?=?a[j],?a[j]?=?a[j-1],?a[j-1]?=?tmp;
????????????????sorted?=?0;
????????????}???
????????}???
????????if?(sorted)
????????????return?;
????}???
}
5 計(jì)數(shù)排序

/**
?*?計(jì)數(shù)排序
?*/
void?countingSort(int?a[],?int?n)?
{
????int?i,?j;
????int?*b?=?(int?*)malloc(sizeof(int)?*?n);
????int?k?=?maxOfIntArray(a,?n);?//?求數(shù)組最大元素
????int?*c?=?(int?*)malloc(sizeof(int)?*?(k+1));??//輔助數(shù)組
????for?(i?=?0;?i?<=?k;?i++)
????????c[i]?=?0;
????for?(j?=?0;?j?????????c[a[j]]?=?c[a[j]]?+?1;?//c[i]包含等于i的元素個(gè)數(shù)
????for?(i?=?1;?i?<=?k;?i++)
????????c[i]?=?c[i]?+?c[i-1];??//c[i]包含小于等于i的元素個(gè)數(shù)
????for?(j?=?n-1;?j?>=?0;?j--)?{??//?賦值語(yǔ)句
????????b[c[a[j]]-1]?=?a[j];?//結(jié)果存在b[0...n-1]中
????????c[a[j]]?=?c[a[j]]?-?1;
????}
????/*方便測(cè)試代碼,這一步賦值不是必須的*/
????for?(i?=?0;?i?????????a[i]?=?b[i];
????}
????free(b);
????free(c);
}
6 歸并排序
/*
?*?歸并排序-遞歸
?*?*/
void?mergeSort(int?a[],?int?l,?int?u)?
{
????if?(l?????????int?m?=?l?+?(u-l)/2;
????????mergeSort(a,?l,?m);
????????mergeSort(a,?m?+?1,?u);
????????merge(a,?l,?m,?u);
????}
}
/**
?*?歸并排序合并函數(shù)
?*/
void?merge(int?a[],?int?l,?int?m,?int?u)?
{
????int?n1?=?m?-?l?+?1;
????int?n2?=?u?-?m;
????int?left[n1],?right[n2];
????int?i,?j;
????for?(i?=?0;?i?left?holds?a[l..m]?*/
????????left[i]?=?a[l?+?i];
????for?(j?=?0;?j?right?holds?a[m+1..u]?*/
????????right[j]?=?a[m?+?1?+?j];
????i?=?j?=?0;
????int?k?=?l;
????while?(i?????????if?(left[i]?right[j])
????????????a[k++]?=?left[i++];
????????else
????????????a[k++]?=?right[j++];
????}
????while?(i?left[]?is?not?exhausted?*/
????????a[k++]?=?left[i++];
????while?(j?right[]?is?not?exhausted?*/
????????a[k++]?=?right[j++];
}
/**
?*?歸并排序-非遞歸
?*/
void?mergeSortIter(int?a[],?int?n)
{
????int?i,?s=2;
????while?(s?<=?n)?{
????????i?=?0;
????????while?(i+s?<=?n){
????????????merge(a,?i,?i+s/2-1,?i+s-1);
????????????i?+=?s;
????????}
????????//處理末尾殘余部分
????????merge(a,?i,?i+s/2-1,?n-1);
????????s*=2;
????}
????//最后再?gòu)念^到尾處理一遍
????merge(a,?0,?s/2-1,?n-1);
}
7 基數(shù)排序、桶排序


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